algebrica-org-pages/increasing-and-decreasing-functions.md

# Increasing, Decreasing and Monotonic Functions

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https://algebrica.org/increasing-and-decreasing-functions/
Fetched from algebrica.org post 8284; source modified 2025-12-06T17:55:43.

## Introduction

Understanding the behavior of [functions](../functions.md) is fundamental in mathematics. Depending on how their output values change with respect to the input, functions can be classified as:

-   increasing
-   decreasing
-   monotonic

##### These characteristics are closely tied to the geometry of their graphs in the Cartesian plane, revealing whether a function rises, falls, or maintains a consistent directional trend.

* * *

Let \\( y = f(x)\\) be a function defined on a [domain](../determining-the-domain-of-a-function.md) \\( X \\subseteq \\mathbb{R} \\). We say that \\( f \\) is **strictly increasing** on an interval \\(I \\subseteq X \\) if, for any two values \\( x\_1, x\_2 \\in I \\) such that \\( x\_1 < x\_2 \\), the following condition holds:

\\[
f(x\_1) < f(x\_2)
\\]

![](https://algebrica.org/wp-content/uploads/resources/images/increasing-decreasing-functions-1-3.png)

This means that as the input \\( x \\) increases within the interval \\( I \\), the output \\( f(x) \\) also strictly increases, without any flat or decreasing segments.

* * *

Let \\( y = f(x) \\) be a function defined on a domain \\( X \\subseteq \\mathbb{R} \\). We say that \\( f \\) is **strictly decreasing** on an interval \\( I \\subseteq X \\) if, for any two values \\( x\_1, x\_2 \\in I \\) such that \\( x\_1 < x\_2 \\), the following condition holds:

\\[
f(x\_1) > f(x\_2)
\\]

![](https://algebrica.org/wp-content/uploads/resources/images/increasing-decreasing-functions-2-1.png)

This means that as the input \\( x \\) increases within the interval \\( I \\), the output \\( f(x) \\) strictly decreases, with no flat or increasing sections.

* * *

A function with domain \\( X \\subseteq \\mathbb{R} \\) is said to be **strictly monotonic** on an interval \\( I \\subseteq X \\) if it is either strictly increasing or strictly decreasing throughout the entire interval \\( I \\), with no change in direction or flat segments. In other words, the function maintains a consistent trend, either upward or downward, across \\( I \\).

To summarize: let \\( X \\subseteq \\mathbb{R} \\), and let \\( x\_1, x\_2 \\in X \\) with \\( x\_1 < x\_2 \\). Then the function \\( f : X \\to \\mathbb{R} \\) is said to be:

-   Increasing: if \\( f(x\_1) \\leq f(x\_2) \\).
-   Strictly increasing: if \\( f(x\_1) < f(x\_2) \\).
-   Decreasing: if \\( f(x\_1) \\geq f(x\_2) \\).
-   Strictly decreasing: if \\( f(x\_1) > f(x\_2) \\).
-   (Strictly) monotonic: if the function is either (strictly) increasing or (strictly) decreasing.

## Derivatives and monotonic behavior

We know that [derivatives](../derivatives.md) are used to describe the shape and graph of functions. In particular, the first derivative of a function, \\( f’(x) \\), can indicate the intervals where the original function \\( f(x) \\) is increasing and where it is decreasing.

In general, given a function \\( y = f(x) \\) that is [continuous](../continuous-functions.md) on an interval \\( I \\) and differentiable at the interior points of \\( I \\):

-   If \\( f’(x) > 0 \\) for every \\( x \\) in the interior of \\( I \\), then \\( f(x) \\) is increasing on \\( I \\).
-   If \\( f’(x) < 0 \\) for every \\( x \\) in the interior of \\( I \\), then \\( f(x) \\) is decreasing on \\( I \\).
-   If \\( f’(x) = 0 \\) for every \\( x \\) in the interior of \\( I \\), then \\( f(x) \\) is constant on \\( I \\).

* * *

To demonstrate these properties, we use the [Lagrange’s Theorem](../lagrange-theorem.md). Let’s imagine having two points \\( a \\) and \\( b \\) \\(\\in I \\) with \\( a < b \\). Next, let us consider a point \\( c \\) belonging to the interval \\( \]a, b\[ \\).

![](https://algebrica.org/wp-content/uploads/resources/images/increasing-decreasing-function.png)

By the Lagrange’s Theorem, we have:

\\[
f^{\\prime}\\left (c \\right ) = \\frac{f(b) - f(a)}{b - a}
\\]

Since we have \\( b - a > 0 \\) and \\( f’\\left (c \\right) > 0 \\), it follows that \\( f(b) - f(a) > 0 \\), which implies \\( f(b) > f(a) \\). Since \\( a \\) and \\( b \\) are arbitrary points in \\( I \\), the function is increasing on \\( I \\).

Similarly, considering the opposite case, since we have \\( b - a > 0 \\) and \\( f’\\left( c \\right) < 0 \\), it follows that \\( f(b) - f(a) < 0 \\), which implies \\( f(b) < f(a) \\). Since \\( a \\) and \\( b \\) are arbitrary points in \\( I \\), the function is decreasing on \\( I \\).

## Example 1

Let us consider the function:

\\[
f(x) = \\frac{x^4}{4} - \\frac{x^2}{2}
\\]

* * *

Let us compute its derivative:

\\[
f’(x) = x(x^2 - 1)
\\]

Let us find the intervals where the derivative is greater than zero. We have:

\\[
x > 0
\\]



\\[
x^2 - 1 > 0 \\implies x < -1 \\text{ or } x > 1
\\]

By multiplying the signs of the first and second factors, we obtain the intervals where the derivative is positive.

\\[
-1
\\]

\\[
0
\\]

\\[
1
\\]

\\( x > 0 \\)

\\( \\boldsymbol{-} \\)

\\( \\boldsymbol{-} \\)

\\( \\boldsymbol{+} \\)

\\( \\boldsymbol{+} \\)

\\( x^2 - 1 > 0 \\)

\\( \\boldsymbol{+} \\)

\\( \\boldsymbol{-} \\)

\\( \\boldsymbol{-} \\)

\\( \\boldsymbol{+} \\)

\\[
f’(x)
\\]

\\( \\boldsymbol{-}\\)

\\( \\boldsymbol{+} \\)

\\( \\boldsymbol{-} \\)

\\(\\boldsymbol{+} \\)

Therefore, the derivative \\( x(x^2 - 1) \\) is positive for:

\\[
x \\in (-1,0) \\cup (1,+\\infty)
\\]

##### For the sake of completeness, we recall that the sign analysis of a function, as in the given example, requires examining the signs of its individual factors and determining the overall sign for each interval by computing the product of these signs.

* * *

Graphically, its behavior is as follows:

![](https://algebrica.org/wp-content/uploads/resources/images/increasing-decreasing-functions-2.png)

Therefore, the function is increasing in the interval \\((-1,0) \\cup (1,+\\infty)\\) and decreasing in the interval \\((-\\infty, -1) \\cup (0,1)\\).